A-roller-coaster-has-a-vertical-loop-with-radius-of-15m Now
The centripetal acceleration must equal the acceleration due to gravity to keep the car from falling:
) and the normal force from the track. For the "minimum" speed (the point where the car just stays on the track), the normal force is zero. We use: ≈is approximately equal to 2. Set up the equation a-roller-coaster-has-a-vertical-loop-with-radius-of-15m
v=9.8⋅15v equals the square root of 9.8 center dot 15 end-root v=147v equals the square root of 147 end-root v≈12.12 m/sv is approximately equal to 12.12 m/s ✅ Final Result The centripetal acceleration must equal the acceleration due